What are the solutions to the equation x^2-24x-12=0 ?

The solutions to the equation x^2-24x-12=0 are x=2(6+sqrt(39)),x=2(6-sqrt(39))

Find the zeros of x^2-24x-12=0

The zeros of x^2-24x-12=0 are x=2(6+sqrt(39)),x=2(6-sqrt(39))

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x^{2} - 24 x - 12 = 0

x = 2 (6 + 39), x = 2 (6 - 39)

Decimal Notation

x = 24.48999 \dots, x = - 0.48999 \dots

Solution steps

x^{2} - 24 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 24)^{2} - 4 \cdot 1 \cdot (- 12) = 439

x_{1, 2} = \frac{- ( - 24 ) \pm 4 39}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 4 39}{2 \cdot 1}, x_{2} = \frac{- ( - 24 ) - 4 39}{2 \cdot 1}

x = \frac{- ( - 24 ) + 4 39}{2 \cdot 1} : 2 (6 + 39)

x = \frac{- ( - 24 ) - 4 39}{2 \cdot 1} : 2 (6 - 39)

The solutions to the quadratic equation are:

x = 2 (6 + 39), x = 2 (6 - 39)

m^{2} n^{2} + ab + a n^{2} + b m^{2}

y^{2} + 2 x y - 63 x^{2}

36 a^{7} b^{5} + 9 a b^{2} - 72 a b^{6}

0.25 (2 x + 4) = 5

13384.63 (\frac{0.075}{12})

What are the solutions to the equation x^2-24x-12=0 ?
The solutions to the equation x^2-24x-12=0 are x=2(6+sqrt(39)),x=2(6-sqrt(39))
Find the zeros of x^2-24x-12=0
The zeros of x^2-24x-12=0 are x=2(6+sqrt(39)),x=2(6-sqrt(39))