What are the solutions to the equation roots x^3-3x^2+2x=0 ?

The solutions to the equation roots x^3-3x^2+2x=0 are x=0,x=1,x=2

Find the zeros of roots x^3-3x^2+2x=0

The zeros of roots x^3-3x^2+2x=0 are x=0,x=1,x=2

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roots

x^{3} - 3 x^{2} + 2 x = 0

x = 0, x = 1, x = 2

Solution steps

x^{3} - 3 x^{2} + 2 x = 0

Factor

x^{3} - 3 x^{2} + 2 x : x (x - 1) (x - 2)

x (x - 1) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 1 = 0 or x - 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = 1, x = 2

(1 + x)^{3} = 1.08056955

4 - 3.6 x + 3.6 x^{2} - 1.2 x^{3} = 0

4 x^{3} - 12 x^{2} + 11 x - 3 = 0

5 x^{3} + 8 x^{2} - 2 = 0

y^{3} - 10 y^{2} + 21 y = 0

What are the solutions to the equation roots x^3-3x^2+2x=0 ?
The solutions to the equation roots x^3-3x^2+2x=0 are x=0,x=1,x=2
Find the zeros of roots x^3-3x^2+2x=0
The zeros of roots x^3-3x^2+2x=0 are x=0,x=1,x=2