What are the solutions to the equation 2x^3-3x-12x=0 ?

The solutions to the equation 2x^3-3x-12x=0 are x=0,x=-sqrt(15/2),x=sqrt(15/2)

Find the zeros of 2x^3-3x-12x=0

The zeros of 2x^3-3x-12x=0 are x=0,x=-sqrt(15/2),x=sqrt(15/2)

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2 x^{3} - 3 x - 12 x = 0

x = 0, x = - \frac{15}{2}, x = \frac{15}{2}

Decimal Notation

x = 0, x = - 2.73861 \dots, x = 2.73861 \dots

Solution steps

2 x^{3} - 3 x - 12 x = 0

Factor

2 x^{3} - 3 x - 12 x : x (2 x + 15) (2 x - 15)

x (2 x + 15) (2 x - 15) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x + 15 = 0 or 2 x - 15 = 0

Solve

2 x + 15 = 0 : x = - \frac{15}{2}

Solve

2 x - 15 = 0 : x = \frac{15}{2}

The solutions are

x = 0, x = - \frac{15}{2}, x = \frac{15}{2}

x^{5} + 2 x^{3} + 2 x^{2} = 0

x^{3} - x^{2} - x - 3 = 0

m^{3} - m^{2} + 8 m - 8 = 0

z^{4} = 82 + 82 i

0 = x^{3} - 5 x^{2} - x + 5

What are the solutions to the equation 2x^3-3x-12x=0 ?
The solutions to the equation 2x^3-3x-12x=0 are x=0,x=-sqrt(15/2),x=sqrt(15/2)
Find the zeros of 2x^3-3x-12x=0
The zeros of 2x^3-3x-12x=0 are x=0,x=-sqrt(15/2),x=sqrt(15/2)