What are the solutions to the equation 3x^3-24x^2+36x=0 ?

The solutions to the equation 3x^3-24x^2+36x=0 are x=0,x=2,x=6

Find the zeros of 3x^3-24x^2+36x=0

The zeros of 3x^3-24x^2+36x=0 are x=0,x=2,x=6

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3 x^{3} - 24 x^{2} + 36 x = 0

x = 0, x = 2, x = 6

Solution steps

3 x^{3} - 24 x^{2} + 36 x = 0

Factor

3 x^{3} - 24 x^{2} + 36 x : 3 x (x - 2) (x - 6)

3 x (x - 2) (x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 2 = 0 or x - 6 = 0

Solve

x - 2 = 0 : x = 2

Solve

x - 6 = 0 : x = 6

The solutions are

x = 0, x = 2, x = 6

x^{2} (x + 1)^{2} (x^{2} + 1)^{3} = 0

x^{5} = e^{10}

2 x^{4} + 5 x^{3} + 9 x^{2} + 15 x + 9

x^{4} - 8 x + 1 = 0

x^{4} + 3 x^{3} + 3 x^{2} + 2 x + 1 = 0

What are the solutions to the equation 3x^3-24x^2+36x=0 ?
The solutions to the equation 3x^3-24x^2+36x=0 are x=0,x=2,x=6
Find the zeros of 3x^3-24x^2+36x=0
The zeros of 3x^3-24x^2+36x=0 are x=0,x=2,x=6