What are the solutions to the equation 2x^3-x^2-6x=0 ?

The solutions to the equation 2x^3-x^2-6x=0 are x=0,x=-3/2 ,x=2

Find the zeros of 2x^3-x^2-6x=0

The zeros of 2x^3-x^2-6x=0 are x=0,x=-3/2 ,x=2

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2 x^{3} - x^{2} - 6 x = 0

x = 0, x = - \frac{3}{2}, x = 2

Decimal Notation

x = 0, x = - 1.5, x = 2

Solution steps

2 x^{3} - x^{2} - 6 x = 0

Factor

2 x^{3} - x^{2} - 6 x : x (2 x + 3) (x - 2)

x (2 x + 3) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x + 3 = 0 or x - 2 = 0

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = - \frac{3}{2}, x = 2

x^{8} = - 256

x^{4} - 4 x^{3} + 4 x^{2}

(x^{2} - 36)^{2} + (x^{2} + 4 x - 12)^{2} = 0

4 x^{3} + 6 x^{2} - 72 x - 3 = 0

2 x^{3} - 16 x^{2} - 40 x = 0

What are the solutions to the equation 2x^3-x^2-6x=0 ?
The solutions to the equation 2x^3-x^2-6x=0 are x=0,x=-3/2 ,x=2
Find the zeros of 2x^3-x^2-6x=0
The zeros of 2x^3-x^2-6x=0 are x=0,x=-3/2 ,x=2