What are the solutions to the equation roots x^3+3x^2+9x+27 ?

The solutions to the equation roots x^3+3x^2+9x+27 are x=-3,x=3i,x=-3i

Find the zeros of roots x^3+3x^2+9x+27

The zeros of roots x^3+3x^2+9x+27 are x=-3,x=3i,x=-3i

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roots

x^{3} + 3 x^{2} + 9 x + 27

x = - 3, x = 3 i, x = - 3 i

Solution steps

x^{3} + 3 x^{2} + 9 x + 27

The roots are the intercepts with the x-axis

(y = 0)

x^{3} + 3 x^{2} + 9 x + 27 = 0

Factor

x^{3} + 3 x^{2} + 9 x + 27 : (x + 3) (x^{2} + 9)

(x + 3) (x^{2} + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x^{2} + 9 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x^{2} + 9 = 0 : x = 3 i, x = - 3 i

The solutions are

x = - 3, x = 3 i, x = - 3 i

4 x^{3} - 8 x + 1 = 0

2 m x^{4} + 3 n x^{4} + 10 m + 15 n

A, A^{4} t = m - R^{2}

x^{3} + 4 x

x^{3} - 23 x^{2} + 22 x = 0

What are the solutions to the equation roots x^3+3x^2+9x+27 ?
The solutions to the equation roots x^3+3x^2+9x+27 are x=-3,x=3i,x=-3i
Find the zeros of roots x^3+3x^2+9x+27
The zeros of roots x^3+3x^2+9x+27 are x=-3,x=3i,x=-3i