What are the solutions to the equation x^3-4x=5x^2-20 ?

The solutions to the equation x^3-4x=5x^2-20 are x=5,x=-2,x=2

Find the zeros of x^3-4x=5x^2-20

The zeros of x^3-4x=5x^2-20 are x=5,x=-2,x=2

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x^{3} - 4 x = 5 x^{2} - 20

x = 5, x = - 2, x = 2

Solution steps

x^{3} - 4 x = 5 x^{2} - 20

Move

20

to the left side

x^{3} - 4 x + 20 = 5 x^{2}

Move

5 x^{2}

to the left side

x^{3} - 4 x + 20 - 5 x^{2} = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

x^{3} - 5 x^{2} - 4 x + 20 = 0

Factor

x^{3} - 5 x^{2} - 4 x + 20 : (x - 5) (x + 2) (x - 2)

(x - 5) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 5 = 0 or x + 2 = 0 or x - 2 = 0

Solve

x - 5 = 0 : x = 5

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 5, x = - 2, x = 2

1 - 3 x + x^{2} - x^{3} = x

5 x^{3} - 3 x^{2} + 180 x - 108

y, x^{3} = 4 y^{2} + 4 y - 3

x^{4} - 128 \cdot x^{2} - 8192 \cdot x - 61440 = 0

6 x^{3} - 5 x - 1 = 0

What are the solutions to the equation x^3-4x=5x^2-20 ?
The solutions to the equation x^3-4x=5x^2-20 are x=5,x=-2,x=2
Find the zeros of x^3-4x=5x^2-20
The zeros of x^3-4x=5x^2-20 are x=5,x=-2,x=2