What are the solutions to the equation n^3-n=7n^2-7 ?

The solutions to the equation n^3-n=7n^2-7 are n=7,n=-1,n=1

Find the zeros of n^3-n=7n^2-7

The zeros of n^3-n=7n^2-7 are n=7,n=-1,n=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

n^{3} - n = 7 n^{2} - 7

n = 7, n = - 1, n = 1

Solution steps

n^{3} - n = 7 n^{2} - 7

Move

7

to the left side

n^{3} - n + 7 = 7 n^{2}

Move

7 n^{2}

to the left side

n^{3} - n + 7 - 7 n^{2} = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

n^{3} - 7 n^{2} - n + 7 = 0

Factor

n^{3} - 7 n^{2} - n + 7 : (n - 7) (n + 1) (n - 1)

(n - 7) (n + 1) (n - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

n - 7 = 0 or n + 1 = 0 or n - 1 = 0

Solve

n - 7 = 0 : n = 7

Solve

n + 1 = 0 : n = - 1

Solve

n - 1 = 0 : n = 1

The solutions are

n = 7, n = - 1, n = 1

92265.19 = 50500 (1 + x)^{29}

y, x (25 - 4 x^{2} - 4 y^{2}) = 0

x^{3} + 5 x - 6 = 0

z^{7} + 1 = 0

z^{9} - 10 z^{6} + 17 z^{3} - 8 = 0

What are the solutions to the equation n^3-n=7n^2-7 ?
The solutions to the equation n^3-n=7n^2-7 are n=7,n=-1,n=1
Find the zeros of n^3-n=7n^2-7
The zeros of n^3-n=7n^2-7 are n=7,n=-1,n=1