What are the solutions to the equation 2x^2+9x+4=0 ?

The solutions to the equation 2x^2+9x+4=0 are x=-1/2 ,x=-4

Find the zeros of 2x^2+9x+4=0

The zeros of 2x^2+9x+4=0 are x=-1/2 ,x=-4

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2 x^{2} + 9 x + 4 = 0

x = - \frac{1}{2}, x = - 4

Decimal Notation

x = - 0.5, x = - 4

Solution steps

2 x^{2} + 9 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 \cdot 4}{2 \cdot 2}

9^{2} - 4 \cdot 2 \cdot 4 = 7

x_{1, 2} = \frac{- 9 \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 9 + 7}{2 \cdot 2}, x_{2} = \frac{- 9 - 7}{2 \cdot 2}

x = \frac{- 9 + 7}{2 \cdot 2} : - \frac{1}{2}

x = \frac{- 9 - 7}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - 4

lo g_{2} (\frac{1}{3})

((- 2)^{2})^{\frac{1}{2}}

50 x^{5} - 18 x

- 5 x^{2} + x + 2 = 0

\frac{3 ^{2} - 16}{3 - 4}

What are the solutions to the equation 2x^2+9x+4=0 ?
The solutions to the equation 2x^2+9x+4=0 are x=-1/2 ,x=-4
Find the zeros of 2x^2+9x+4=0
The zeros of 2x^2+9x+4=0 are x=-1/2 ,x=-4