What are the solutions to the equation roots x^3-3x^2+7x-5 ?

The solutions to the equation roots x^3-3x^2+7x-5 are x=1,x=1+2i,x=1-2i

Find the zeros of roots x^3-3x^2+7x-5

The zeros of roots x^3-3x^2+7x-5 are x=1,x=1+2i,x=1-2i

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roots

x^{3} - 3 x^{2} + 7 x - 5

x = 1, x = 1 + 2 i, x = 1 - 2 i

Solution steps

x^{3} - 3 x^{2} + 7 x - 5

The roots are the intercepts with the x-axis

(y = 0)

x^{3} - 3 x^{2} + 7 x - 5 = 0

Factor

x^{3} - 3 x^{2} + 7 x - 5 : (x - 1) (x^{2} - 2 x + 5)

(x - 1) (x^{2} - 2 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x^{2} - 2 x + 5 = 0

Solve

x - 1 = 0 : x = 1

Solve

x^{2} - 2 x + 5 = 0 : x = 1 + 2 i, x = 1 - 2 i

The solutions are

x = 1, x = 1 + 2 i, x = 1 - 2 i

\frac{1}{3} x^{3} + x^{2} + 1 = 0

(x - 1)^{2} (x - 2) = 0

20 x^{3} + 44 x^{2} - 17 x - 5 = 0

4 x^{5} - 12 x^{4} + 8 x^{3} = 0

x^{6} + x^{5} - 5 x^{4} - x^{3} + 8 x^{2} - 4 x = 0

What are the solutions to the equation roots x^3-3x^2+7x-5 ?
The solutions to the equation roots x^3-3x^2+7x-5 are x=1,x=1+2i,x=1-2i
Find the zeros of roots x^3-3x^2+7x-5
The zeros of roots x^3-3x^2+7x-5 are x=1,x=1+2i,x=1-2i