What are the solutions to the equation 2x^4+x^3-24x^2+20x+16=0 ?

The solutions to the equation 2x^4+x^3-24x^2+20x+16=0 are x=2,x=-1/2 ,x=-4

Find the zeros of 2x^4+x^3-24x^2+20x+16=0

The zeros of 2x^4+x^3-24x^2+20x+16=0 are x=2,x=-1/2 ,x=-4

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2 x^{4} + x^{3} - 24 x^{2} + 20 x + 16 = 0

x = 2, x = - \frac{1}{2}, x = - 4

Decimal Notation

x = 2, x = - 0.5, x = - 4

Solution steps

2 x^{4} + x^{3} - 24 x^{2} + 20 x + 16 = 0

Factor

2 x^{4} + x^{3} - 24 x^{2} + 20 x + 16 : (x - 2)^{2} (2 x + 1) (x + 4)

(x - 2)^{2} (2 x + 1) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 2 x + 1 = 0 or x + 4 = 0

Solve

x - 2 = 0 : x = 2

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

x + 4 = 0 : x = - 4

The solutions are

x = 2, x = - \frac{1}{2}, x = - 4

2 x^{4} - 5 x^{2} - 3 = 0

5 x^{4} + 3 x^{2} + x^{2} - x = 0

x^{3} - 3 x = - 2

2 x^{4} + 7 x^{3} - 2 x^{2} - 19 x - 12 = 0

x^{4} + 4 x^{3} + 5 x^{2} + 4 x + 1 = 0

What are the solutions to the equation 2x^4+x^3-24x^2+20x+16=0 ?
The solutions to the equation 2x^4+x^3-24x^2+20x+16=0 are x=2,x=-1/2 ,x=-4
Find the zeros of 2x^4+x^3-24x^2+20x+16=0
The zeros of 2x^4+x^3-24x^2+20x+16=0 are x=2,x=-1/2 ,x=-4