What are the solutions to the equation n^3-9n^2-n+9=0 ?

The solutions to the equation n^3-9n^2-n+9=0 are n=9,n=-1,n=1

Find the zeros of n^3-9n^2-n+9=0

The zeros of n^3-9n^2-n+9=0 are n=9,n=-1,n=1

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n^{3} - 9 n^{2} - n + 9 = 0

n = 9, n = - 1, n = 1

Solution steps

n^{3} - 9 n^{2} - n + 9 = 0

Factor

n^{3} - 9 n^{2} - n + 9 : (n - 9) (n + 1) (n - 1)

(n - 9) (n + 1) (n - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

n - 9 = 0 or n + 1 = 0 or n - 1 = 0

Solve

n - 9 = 0 : n = 9

Solve

n + 1 = 0 : n = - 1

Solve

n - 1 = 0 : n = 1

The solutions are

n = 9, n = - 1, n = 1

y, 4 x^{3} - 16 y = 4 y^{3} - 16 x

4 x^{7} - 64 x^{3} = 0

N, b a^{2} + 3 = N^{3}

(x - 1)^{4} - 2 (x - 1)^{2} - 3 = 0

5 t^{4} + 15 t^{2} + 50 = 0

What are the solutions to the equation n^3-9n^2-n+9=0 ?
The solutions to the equation n^3-9n^2-n+9=0 are n=9,n=-1,n=1
Find the zeros of n^3-9n^2-n+9=0
The zeros of n^3-9n^2-n+9=0 are n=9,n=-1,n=1