What are the solutions to the equation -4x^3+24x=0 ?

The solutions to the equation -4x^3+24x=0 are x=0,x=-sqrt(6),x=sqrt(6)

Find the zeros of -4x^3+24x=0

The zeros of -4x^3+24x=0 are x=0,x=-sqrt(6),x=sqrt(6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 4 x^{3} + 24 x = 0

x = 0, x = - 6, x = 6

Decimal Notation

x = 0, x = - 2.44948 \dots, x = 2.44948 \dots

Solution steps

- 4 x^{3} + 24 x = 0

Factor

- 4 x^{3} + 24 x : - 4 x (x + 6) (x - 6)

- 4 x (x + 6) (x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 6 = 0 or x - 6 = 0

Solve

x + 6 = 0 : x = - 6

Solve

x - 6 = 0 : x = 6

The solutions are

x = 0, x = - 6, x = 6

x^{4} + x = 3

x^{3} = 13 x^{2} - 42 x

s^{3} + 3 s^{2} + 3 s - 7 = 0

4 x^{3} + 24 x + 36 = 0

x^{3} = 76

What are the solutions to the equation -4x^3+24x=0 ?
The solutions to the equation -4x^3+24x=0 are x=0,x=-sqrt(6),x=sqrt(6)
Find the zeros of -4x^3+24x=0
The zeros of -4x^3+24x=0 are x=0,x=-sqrt(6),x=sqrt(6)