What are the solutions to the equation 1-x-x^2+x^3=0 ?

The solutions to the equation 1-x-x^2+x^3=0 are x=1,x=-1

Find the zeros of 1-x-x^2+x^3=0

The zeros of 1-x-x^2+x^3=0 are x=1,x=-1

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1 - x - x^{2} + x^{3} = 0

x = 1, x = - 1

Solution steps

1 - x - x^{2} + x^{3} = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

x^{3} - x^{2} - x + 1 = 0

Factor

x^{3} - x^{2} - x + 1 : (x - 1)^{2} (x + 1)

(x - 1)^{2} (x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 1 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 1 = 0 : x = - 1

The solutions are

x = 1, x = - 1

\frac{80}{7} (x^{3}) = 70

2 x^{3} + 54 = 0

3 (x^{2} + 5 x + 1)^{2} + 2 x^{2} + 10 x = 3

x^{3} - 6 x - 4

x^{4} = x^{3}

What are the solutions to the equation 1-x-x^2+x^3=0 ?
The solutions to the equation 1-x-x^2+x^3=0 are x=1,x=-1
Find the zeros of 1-x-x^2+x^3=0
The zeros of 1-x-x^2+x^3=0 are x=1,x=-1