What are the solutions to the equation 20=4x^3-12x^2-40x+20 ?

The solutions to the equation 20=4x^3-12x^2-40x+20 are x=0,x=-2,x=5

Find the zeros of 20=4x^3-12x^2-40x+20

The zeros of 20=4x^3-12x^2-40x+20 are x=0,x=-2,x=5

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20 = 4 x^{3} - 12 x^{2} - 40 x + 20

x = 0, x = - 2, x = 5

Solution steps

20 = 4 x^{3} - 12 x^{2} - 40 x + 20

Switch sides

4 x^{3} - 12 x^{2} - 40 x + 20 = 20

Move

20

to the right side

4 x^{3} - 12 x^{2} - 40 x = 0

Factor

4 x^{3} - 12 x^{2} - 40 x : 4 x (x + 2) (x - 5)

4 x (x + 2) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 2 = 0 or x - 5 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 5 = 0 : x = 5

The solutions are

x = 0, x = - 2, x = 5

y^{3} = 9 y

b^{3} = 125

0 = x^{4} + 8 x^{2} - 9

- 2 x^{3} + 6 x^{2} - 3 = 0

x^{3} = x^{2} - 1

What are the solutions to the equation 20=4x^3-12x^2-40x+20 ?
The solutions to the equation 20=4x^3-12x^2-40x+20 are x=0,x=-2,x=5
Find the zeros of 20=4x^3-12x^2-40x+20
The zeros of 20=4x^3-12x^2-40x+20 are x=0,x=-2,x=5