What are the solutions to the equation 3x^3+4x^2+27x+36=0 ?

The solutions to the equation 3x^3+4x^2+27x+36=0 are x=-4/3 ,x=3i,x=-3i

Find the zeros of 3x^3+4x^2+27x+36=0

The zeros of 3x^3+4x^2+27x+36=0 are x=-4/3 ,x=3i,x=-3i

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3 x^{3} + 4 x^{2} + 27 x + 36 = 0

x = - \frac{4}{3}, x = 3 i, x = - 3 i

Solution steps

3 x^{3} + 4 x^{2} + 27 x + 36 = 0

Factor

3 x^{3} + 4 x^{2} + 27 x + 36 : (3 x + 4) (x^{2} + 9)

(3 x + 4) (x^{2} + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 4 = 0 or x^{2} + 9 = 0

Solve

3 x + 4 = 0 : x = - \frac{4}{3}

Solve

x^{2} + 9 = 0 : x = 3 i, x = - 3 i

The solutions are

x = - \frac{4}{3}, x = 3 i, x = - 3 i

d x^{3}

x^{3} - 3 x^{2} + x - 3 = 0

10 x + 0.5 x^{2} - 0.001 x^{3} - 5000 = 0

x^{4} - x^{2} = 7 x^{2} + 9

- x^{3} + 4 x^{2} - 9 x - 6

What are the solutions to the equation 3x^3+4x^2+27x+36=0 ?
The solutions to the equation 3x^3+4x^2+27x+36=0 are x=-4/3 ,x=3i,x=-3i
Find the zeros of 3x^3+4x^2+27x+36=0
The zeros of 3x^3+4x^2+27x+36=0 are x=-4/3 ,x=3i,x=-3i