What are the solutions to the equation 24x^3-3=0 ?

The solutions to the equation 24x^3-3=0 are x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i

Find the zeros of 24x^3-3=0

The zeros of 24x^3-3=0 are x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i

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24 x^{3} - 3 = 0

x = \frac{1}{2}, x = - \frac{1}{4} + \frac{3}{4} i, x = - \frac{1}{4} - \frac{3}{4} i

Solution steps

24 x^{3} - 3 = 0

Move

3

to the right side

24 x^{3} = 3

Divide both sides by

24

x^{3} = \frac{1}{8}

For

x^{3} = f (a)

the solutions are

Simplify

x = \frac{1}{2}, x = - \frac{1}{4} + \frac{3}{4} i, x = - \frac{1}{4} - \frac{3}{4} i

x^{4} + 62 x^{2} + 128 x + 65 = 0

x^{3} - 11 x^{2} + 26 x - 16 = 0

x^{3} + 4 x^{2} - 5 x - 20 = 0

x^{3} - 3 x^{2} - 13 x + 15

x = x^{3} - x^{2} - x

What are the solutions to the equation 24x^3-3=0 ?
The solutions to the equation 24x^3-3=0 are x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i
Find the zeros of 24x^3-3=0
The zeros of 24x^3-3=0 are x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i