What are the solutions to the equation roots x^3-5x^2+4x-20 ?

The solutions to the equation roots x^3-5x^2+4x-20 are x=5,x=2i,x=-2i

Find the zeros of roots x^3-5x^2+4x-20

The zeros of roots x^3-5x^2+4x-20 are x=5,x=2i,x=-2i

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roots

x^{3} - 5 x^{2} + 4 x - 20

x = 5, x = 2 i, x = - 2 i

Solution steps

x^{3} - 5 x^{2} + 4 x - 20

The roots are the intercepts with the x-axis

(y = 0)

x^{3} - 5 x^{2} + 4 x - 20 = 0

Factor

x^{3} - 5 x^{2} + 4 x - 20 : (x - 5) (x^{2} + 4)

(x - 5) (x^{2} + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 5 = 0 or x^{2} + 4 = 0

Solve

x - 5 = 0 : x = 5

Solve

x^{2} + 4 = 0 : x = 2 i, x = - 2 i

The solutions are

x = 5, x = 2 i, x = - 2 i

500 = 0.02 \frac{t ^{4}}{12}

s^{4} + 60 s^{3} + 1400 s^{2} + 2000 s - 130000 = 0

x^{4} - 12 x^{3} + 77 x^{2} - 260 x + 500 = 0

x^{3} - 5 x^{2} + 11 x - 15 = 0

x, x^{3} = 0

What are the solutions to the equation roots x^3-5x^2+4x-20 ?
The solutions to the equation roots x^3-5x^2+4x-20 are x=5,x=2i,x=-2i
Find the zeros of roots x^3-5x^2+4x-20
The zeros of roots x^3-5x^2+4x-20 are x=5,x=2i,x=-2i