What are the solutions to the equation x^3+0.1x^2+0.4x=1.2 ?

The solutions to the equation x^3+0.1x^2+0.4x=1.2 are x\approx 0.90987…

Find the zeros of x^3+0.1x^2+0.4x=1.2

The zeros of x^3+0.1x^2+0.4x=1.2 are x\approx 0.90987…

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x^{3} + 0.1 x^{2} + 0.4 x = 1.2

x \approx 0.90987 \dots

Solution steps

x^{3} + 0.1 x^{2} + 0.4 x = 1.2

Multiply both sides by

10

10 x^{3} + x^{2} + 4 x = 12

Move

12

to the left side

10 x^{3} + x^{2} + 4 x - 12 = 0

Find one solution for

10 x^{3} + x^{2} + 4 x - 12 = 0

using Newton-Raphson:

x \approx 0.90987 \dots

Apply long division:

\frac{10 x ^{3} + x ^{2} + 4 x - 12}{x - 0.90987 \dots} = 10 x^{2} + 10.09875 \dots x + 13.18861 \dots

10 x^{2} + 10.09875 \dots x + 13.18861 \dots \approx 0

Find one solution for

10 x^{2} + 10.09875 \dots x + 13.18861 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx 0.90987 \dots

5 x^{3} - 9 x^{2} + 28 x + 6 = 0

x^{3} + 2 x^{2} - 3 x - 6

y, 8 y^{3} - 1 = 0

y^{3} - 27 = 0

x^{3} + 5 x^{2} + 4 x + 20 = 0

What are the solutions to the equation x^3+0.1x^2+0.4x=1.2 ?
The solutions to the equation x^3+0.1x^2+0.4x=1.2 are x\approx 0.90987…
Find the zeros of x^3+0.1x^2+0.4x=1.2
The zeros of x^3+0.1x^2+0.4x=1.2 are x\approx 0.90987…