What is ((2^{-3}*4^2)^{-1})/(2^{-1)} ?

The solution to ((2^{-3}*4^2)^{-1})/(2^{-1)} is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((2^{-3}*4^2)^{-1})/(2^{-1)}

simplify

\frac{( 2 ^{- 3} \cdot 4 ^{2} ) ^{- 1}}{2 ^{- 1}}

1

Solution steps

\frac{( 2 ^{- 3} \cdot 4 ^{2} ) ^{- 1}}{2 ^{- 1}}

(2^{- 3} \cdot 4^{2})^{- 1} = \frac{1}{2}

= \frac{\frac{1}{2}}{2 ^{- 1}}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

2^{- 1} = \frac{1}{2}

= \frac{\frac{1}{2}}{\frac{1}{2}}

Apply the fraction rule:

\frac{a}{a} = 1

= 1

\frac{5 ^{6}}{5 ^{3}}

8^{2} + x^{2} = 9^{2}

x - 12 = 7

(v - 9)^{2} - 75 = 0

What is ((2^{-3}*4^2)^{-1})/(2^{-1)} ?
The solution to ((2^{-3}*4^2)^{-1})/(2^{-1)} is 1