What are the solutions to the equation 3x^3+x^2-3x-1=0 ?

The solutions to the equation 3x^3+x^2-3x-1=0 are x=-1/3 ,x=-1,x=1

Find the zeros of 3x^3+x^2-3x-1=0

The zeros of 3x^3+x^2-3x-1=0 are x=-1/3 ,x=-1,x=1

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3 x^{3} + x^{2} - 3 x - 1 = 0

x = - \frac{1}{3}, x = - 1, x = 1

Decimal Notation

x = - 0.33333 \dots, x = - 1, x = 1

Solution steps

3 x^{3} + x^{2} - 3 x - 1 = 0

Factor

3 x^{3} + x^{2} - 3 x - 1 : (3 x + 1) (x + 1) (x - 1)

(3 x + 1) (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 1 = 0 or x + 1 = 0 or x - 1 = 0

Solve

3 x + 1 = 0 : x = - \frac{1}{3}

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = - \frac{1}{3}, x = - 1, x = 1

4 x^{4} + 19 x^{2} - 5 = 0

x^{3} + x^{2} + x + 1 = 0

x^{4} - x^{3} - 30 x^{2}

2 x^{4} + 5 x^{3} - 23 x^{2} + 10 x = 0

x^{3} + 9 x^{2} + 20 x = 0

What are the solutions to the equation 3x^3+x^2-3x-1=0 ?
The solutions to the equation 3x^3+x^2-3x-1=0 are x=-1/3 ,x=-1,x=1
Find the zeros of 3x^3+x^2-3x-1=0
The zeros of 3x^3+x^2-3x-1=0 are x=-1/3 ,x=-1,x=1