What are the solutions to the equation n^3-5n^2-n+5=0 ?

The solutions to the equation n^3-5n^2-n+5=0 are n=5,n=-1,n=1

Find the zeros of n^3-5n^2-n+5=0

The zeros of n^3-5n^2-n+5=0 are n=5,n=-1,n=1

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n^{3} - 5 n^{2} - n + 5 = 0

n = 5, n = - 1, n = 1

Solution steps

n^{3} - 5 n^{2} - n + 5 = 0

Factor

n^{3} - 5 n^{2} - n + 5 : (n - 5) (n + 1) (n - 1)

(n - 5) (n + 1) (n - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

n - 5 = 0 or n + 1 = 0 or n - 1 = 0

Solve

n - 5 = 0 : n = 5

Solve

n + 1 = 0 : n = - 1

Solve

n - 1 = 0 : n = 1

The solutions are

n = 5, n = - 1, n = 1

x^{3} + 3.1798 x^{2} - 670.63 = 0

2 a^{3} - 21 a^{2} - 14 a + 33 = 0

y, x^{2} (x^{2} + y^{2}) = y^{2}

x^{3} - x^{2} + 12 = 0

u^{3} - 13.2 = - 11.8

What are the solutions to the equation n^3-5n^2-n+5=0 ?
The solutions to the equation n^3-5n^2-n+5=0 are n=5,n=-1,n=1
Find the zeros of n^3-5n^2-n+5=0
The zeros of n^3-5n^2-n+5=0 are n=5,n=-1,n=1