What are the solutions to the equation roots 5x^3+5x^2-4x-4 ?

The solutions to the equation roots 5x^3+5x^2-4x-4 are x=-1,x=-2/(sqrt(5)),x= 2/(sqrt(5))

Find the zeros of roots 5x^3+5x^2-4x-4

The zeros of roots 5x^3+5x^2-4x-4 are x=-1,x=-2/(sqrt(5)),x= 2/(sqrt(5))

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roots

5 x^{3} + 5 x^{2} - 4 x - 4

x = - 1, x = - \frac{2}{5}, x = \frac{2}{5}

Solution steps

5 x^{3} + 5 x^{2} - 4 x - 4

The roots are the intercepts with the x-axis

(y = 0)

5 x^{3} + 5 x^{2} - 4 x - 4 = 0

Factor

5 x^{3} + 5 x^{2} - 4 x - 4 : (x + 1) (5 x + 2) (5 x - 2)

(x + 1) (5 x + 2) (5 x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or 5 x + 2 = 0 or 5 x - 2 = 0

Solve

x + 1 = 0 : x = - 1

Solve

5 x + 2 = 0 : x = - \frac{2}{5}

Solve

5 x - 2 = 0 : x = \frac{2}{5}

The solutions are

x = - 1, x = - \frac{2}{5}, x = \frac{2}{5}

n^{3} - n = 3 n^{2} - 3

x^{5} + 4 + 4 i = 0

4 x^{4} + 15 x^{2} - 4 = 0

4 x^{3} - 20 x^{2} - 9 x + 45 = 0

3 x^{5} - 4 x^{4} - 243 x + 324 = 0

What are the solutions to the equation roots 5x^3+5x^2-4x-4 ?
The solutions to the equation roots 5x^3+5x^2-4x-4 are x=-1,x=-2/(sqrt(5)),x= 2/(sqrt(5))
Find the zeros of roots 5x^3+5x^2-4x-4
The zeros of roots 5x^3+5x^2-4x-4 are x=-1,x=-2/(sqrt(5)),x= 2/(sqrt(5))