What are the solutions to the equation -x^3+18x^2-99x+162=0 ?

The solutions to the equation -x^3+18x^2-99x+162=0 are x=3,x=6,x=9

Find the zeros of -x^3+18x^2-99x+162=0

The zeros of -x^3+18x^2-99x+162=0 are x=3,x=6,x=9

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- x^{3} + 18 x^{2} - 99 x + 162 = 0

x = 3, x = 6, x = 9

Solution steps

- x^{3} + 18 x^{2} - 99 x + 162 = 0

Factor

- x^{3} + 18 x^{2} - 99 x + 162 : - (x - 3) (x - 6) (x - 9)

- (x - 3) (x - 6) (x - 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x - 6 = 0 or x - 9 = 0

Solve

x - 3 = 0 : x = 3

Solve

x - 6 = 0 : x = 6

Solve

x - 9 = 0 : x = 9

The solutions are

x = 3, x = 6, x = 9

6 x^{5} - 11 x^{4} - 11 x + 6 = 0

x^{3} - 2 x^{2} - x + 3 = 0

x^{3} + x^{2} - 17 x + 15 = 0

y^{3} - y^{2} + y - 1 = 0

240 x^{3} + 180 x^{2} - 1440 x = 0

What are the solutions to the equation -x^3+18x^2-99x+162=0 ?
The solutions to the equation -x^3+18x^2-99x+162=0 are x=3,x=6,x=9
Find the zeros of -x^3+18x^2-99x+162=0
The zeros of -x^3+18x^2-99x+162=0 are x=3,x=6,x=9