What are the solutions to the equation x^3-7x^2+24x-18=0 ?

The solutions to the equation x^3-7x^2+24x-18=0 are x=1,x=3+3i,x=3-3i

Find the zeros of x^3-7x^2+24x-18=0

The zeros of x^3-7x^2+24x-18=0 are x=1,x=3+3i,x=3-3i

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x^{3} - 7 x^{2} + 24 x - 18 = 0

x = 1, x = 3 + 3 i, x = 3 - 3 i

Solution steps

x^{3} - 7 x^{2} + 24 x - 18 = 0

Factor

x^{3} - 7 x^{2} + 24 x - 18 : (x - 1) (x^{2} - 6 x + 18)

(x - 1) (x^{2} - 6 x + 18) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x^{2} - 6 x + 18 = 0

Solve

x - 1 = 0 : x = 1

Solve

x^{2} - 6 x + 18 = 0 : x = 3 + 3 i, x = 3 - 3 i

The solutions are

x = 1, x = 3 + 3 i, x = 3 - 3 i

x^{7} + x^{6} = 0

3 x^{3} - 2 x^{2} - x = 0

x^{4} + 4 x^{3} + 12 x^{2} + 16 x + 16 = 0

x^{3} - 6 x^{2} + 2 x + 36 = 0

2 - 25 x^{2} = 625 x^{4}

What are the solutions to the equation x^3-7x^2+24x-18=0 ?
The solutions to the equation x^3-7x^2+24x-18=0 are x=1,x=3+3i,x=3-3i
Find the zeros of x^3-7x^2+24x-18=0
The zeros of x^3-7x^2+24x-18=0 are x=1,x=3+3i,x=3-3i