What are the solutions to the equation x^3=x^2+20x ?

The solutions to the equation x^3=x^2+20x are x=0,x=-4,x=5

Find the zeros of x^3=x^2+20x

The zeros of x^3=x^2+20x are x=0,x=-4,x=5

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x^{3} = x^{2} + 20 x

x = 0, x = - 4, x = 5

Solution steps

x^{3} = x^{2} + 20 x

Move

20 x

to the left side

x^{3} - 20 x = x^{2}

Move

x^{2}

to the left side

x^{3} - 20 x - x^{2} = 0

Factor

x^{3} - 20 x - x^{2} : x (x + 4) (x - 5)

x (x + 4) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 4 = 0 or x - 5 = 0

Solve

x + 4 = 0 : x = - 4

Solve

x - 5 = 0 : x = 5

The solutions are

x = 0, x = - 4, x = 5

2 x^{3} - 9 x^{2} + 10 x - 3 = 0

16 x^{3} - 4 x^{2} - 20 x + 5

r^{3} - r^{2} - r + 1 = 0

3 (4 x - 3)^{4} = 1875

r^{4} - 2 r^{3} + r^{2} = 0

What are the solutions to the equation x^3=x^2+20x ?
The solutions to the equation x^3=x^2+20x are x=0,x=-4,x=5
Find the zeros of x^3=x^2+20x
The zeros of x^3=x^2+20x are x=0,x=-4,x=5