What are the solutions to the equation roots x^3-4x^2+5x-2 ?

The solutions to the equation roots x^3-4x^2+5x-2 are x=1,x=2

Find the zeros of roots x^3-4x^2+5x-2

The zeros of roots x^3-4x^2+5x-2 are x=1,x=2

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roots

x^{3} - 4 x^{2} + 5 x - 2

x = 1, x = 2

Solution steps

x^{3} - 4 x^{2} + 5 x - 2

The roots are the intercepts with the x-axis

(y = 0)

x^{3} - 4 x^{2} + 5 x - 2 = 0

Factor

x^{3} - 4 x^{2} + 5 x - 2 : (x - 1)^{2} (x - 2)

(x - 1)^{2} (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x - 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

x - 2 = 0 : x = 2

The solutions are

x = 1, x = 2

4 x^{3} - 16 = 0

5 x^{3} = 6 x^{2}

x^{3} - 5 x^{2} + 2 x + 5

3^{5} \cdot 7^{5} = e^{5}

2 x^{4} - 10 x^{2} + 8 = 0

What are the solutions to the equation roots x^3-4x^2+5x-2 ?
The solutions to the equation roots x^3-4x^2+5x-2 are x=1,x=2
Find the zeros of roots x^3-4x^2+5x-2
The zeros of roots x^3-4x^2+5x-2 are x=1,x=2