What are the solutions to the equation roots x^3-2x^2+16 ?

The solutions to the equation roots x^3-2x^2+16 are x=-2,x=2+2i,x=2-2i

Find the zeros of roots x^3-2x^2+16

The zeros of roots x^3-2x^2+16 are x=-2,x=2+2i,x=2-2i

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roots

x^{3} - 2 x^{2} + 16

x = - 2, x = 2 + 2 i, x = 2 - 2 i

Solution steps

x^{3} - 2 x^{2} + 16

The roots are the intercepts with the x-axis

(y = 0)

x^{3} - 2 x^{2} + 16 = 0

Factor

x^{3} - 2 x^{2} + 16 : (x + 2) (x^{2} - 4 x + 8)

(x + 2) (x^{2} - 4 x + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x^{2} - 4 x + 8 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x^{2} - 4 x + 8 = 0 : x = 2 + 2 i, x = 2 - 2 i

The solutions are

x = - 2, x = 2 + 2 i, x = 2 - 2 i

x^{3} + 6 x^{2} + 12 x + 7 = 0

x^{3} - 3 x^{2} + x - 1 = 0

x^{3} + 9 x^{2} + 15 x + 5 = 0

x^{3} + x^{2} - 12 = 0

x^{4} + 4 x^{3} - 1 = 0

What are the solutions to the equation roots x^3-2x^2+16 ?
The solutions to the equation roots x^3-2x^2+16 are x=-2,x=2+2i,x=2-2i
Find the zeros of roots x^3-2x^2+16
The zeros of roots x^3-2x^2+16 are x=-2,x=2+2i,x=2-2i