What are the solutions to the equation 27x^5-54x^4-72x^3-26x^2-3x=0 ?

The solutions to the equation 27x^5-54x^4-72x^3-26x^2-3x=0 are x=0,x=3,x=-1/3

Find the zeros of 27x^5-54x^4-72x^3-26x^2-3x=0

The zeros of 27x^5-54x^4-72x^3-26x^2-3x=0 are x=0,x=3,x=-1/3

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27 x^{5} - 54 x^{4} - 72 x^{3} - 26 x^{2} - 3 x = 0

x = 0, x = 3, x = - \frac{1}{3}

Decimal Notation

x = 0, x = 3, x = - 0.33333 \dots

Solution steps

27 x^{5} - 54 x^{4} - 72 x^{3} - 26 x^{2} - 3 x = 0

Factor

27 x^{5} - 54 x^{4} - 72 x^{3} - 26 x^{2} - 3 x : x (x - 3) (3 x + 1)^{3}

x (x - 3) (3 x + 1)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 3 = 0 or 3 x + 1 = 0

Solve

x - 3 = 0 : x = 3

Solve

3 x + 1 = 0 : x = - \frac{1}{3}

The solutions are

x = 0, x = 3, x = - \frac{1}{3}

x^{3} - 7 x + 2 = 0

3 x^{4} - 7 x^{3} - 9 x^{2} + 24 x - 4

2 x^{3} - 8 x^{2} + x - 4 = 0

4 x^{3} - 12 x^{2}

x^{6} - x^{3} + x^{2} = 0

What are the solutions to the equation 27x^5-54x^4-72x^3-26x^2-3x=0 ?
The solutions to the equation 27x^5-54x^4-72x^3-26x^2-3x=0 are x=0,x=3,x=-1/3
Find the zeros of 27x^5-54x^4-72x^3-26x^2-3x=0
The zeros of 27x^5-54x^4-72x^3-26x^2-3x=0 are x=0,x=3,x=-1/3