What are the solutions to the equation (x-5)(x-1)(x+3)=0 ?

The solutions to the equation (x-5)(x-1)(x+3)=0 are x=5,x=1,x=-3

Find the zeros of (x-5)(x-1)(x+3)=0

The zeros of (x-5)(x-1)(x+3)=0 are x=5,x=1,x=-3

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(x - 5) (x - 1) (x + 3) = 0

x = 5, x = 1, x = - 3

Solution steps

(x - 5) (x - 1) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 5 = 0 or x - 1 = 0 or x + 3 = 0

Solve

x - 5 = 0 : x = 5

Solve

x - 1 = 0 : x = 1

Solve

x + 3 = 0 : x = - 3

The solutions are

x = 5, x = 1, x = - 3

x^{3} = x^{2} + x - 1

s^{5} + 5 s^{3} + 9 s^{2} + 7 s + 2 = 0

2 x^{3} + x - 18 = 0

x^{4} (x - 4)^{3} = 0

x^{4} - 3 x^{3} - x^{2} - x + 4 = 0

What are the solutions to the equation (x-5)(x-1)(x+3)=0 ?
The solutions to the equation (x-5)(x-1)(x+3)=0 are x=5,x=1,x=-3
Find the zeros of (x-5)(x-1)(x+3)=0
The zeros of (x-5)(x-1)(x+3)=0 are x=5,x=1,x=-3