What are the solutions to the equation 24x^3+6x^2=0 ?

The solutions to the equation 24x^3+6x^2=0 are x=0,x=-1/4

Find the zeros of 24x^3+6x^2=0

The zeros of 24x^3+6x^2=0 are x=0,x=-1/4

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24 x^{3} + 6 x^{2} = 0

x = 0, x = - \frac{1}{4}

Decimal Notation

x = 0, x = - 0.25

Solution steps

24 x^{3} + 6 x^{2} = 0

Factor

24 x^{3} + 6 x^{2} : 6 x^{2} (4 x + 1)

6 x^{2} (4 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 4 x + 1 = 0

Solve

4 x + 1 = 0 : x = - \frac{1}{4}

The solutions are

x = 0, x = - \frac{1}{4}

y, y - x^{3} = 0

3 x^{4} + 2 x^{2} - 8 = 0

x, x^{3} + y^{3} = a^{3}

x^{4} + x^{3} + x^{2} + x = - 1

z^{3} + 32 + 32 i 3 = 0

What are the solutions to the equation 24x^3+6x^2=0 ?
The solutions to the equation 24x^3+6x^2=0 are x=0,x=-1/4
Find the zeros of 24x^3+6x^2=0
The zeros of 24x^3+6x^2=0 are x=0,x=-1/4