What are the solutions to the equation x(2x^2-41)=225 ?

The solutions to the equation x(2x^2-41)=225 are x\approx 6.21337…

Find the zeros of x(2x^2-41)=225

The zeros of x(2x^2-41)=225 are x\approx 6.21337…

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x (2 x^{2} - 41) = 225

x \approx 6.21337 \dots

Solution steps

x (2 x^{2} - 41) = 225

Expand

x (2 x^{2} - 41) : 2 x^{3} - 41 x

2 x^{3} - 41 x = 225

Move

225

to the left side

2 x^{3} - 41 x - 225 = 0

Find one solution for

2 x^{3} - 41 x - 225 = 0

using Newton-Raphson:

x \approx 6.21337 \dots

Apply long division:

\frac{2 x ^{3} - 41 x - 225}{x - 6.21337 \dots} = 2 x^{2} + 12.42675 \dots x + 36.21217 \dots

2 x^{2} + 12.42675 \dots x + 36.21217 \dots \approx 0

Find one solution for

2 x^{2} + 12.42675 \dots x + 36.21217 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx 6.21337 \dots

i x^{4} + x^{2} - i = 0

x^{2} (x + 1)^{2} + x^{2} = 3 (x + 1)^{2}

x^{3} - x = x^{2} + 5 x - 6

x^{4} - 81

x^{6} - 8 x^{5} + 12 x^{4} = 0

What are the solutions to the equation x(2x^2-41)=225 ?
The solutions to the equation x(2x^2-41)=225 are x\approx 6.21337…
Find the zeros of x(2x^2-41)=225
The zeros of x(2x^2-41)=225 are x\approx 6.21337…