What are the solutions to the equation (1-p)^{15}=0 ?

The solutions to the equation (1-p)^{15}=0 are p=1

Find the zeros of (1-p)^{15}=0

The zeros of (1-p)^{15}=0 are p=1

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(1 - p)^{15} = 0

p = 1

Solution steps

(1 - p)^{15} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

1 - p = 0

Solve

1 - p = 0 : p = 1

The solution is

p = 1

12 x^{3} + 24 x^{2} - 12 x - 24 = 0

4 x^{3} - 48 x^{2} = 0

x^{3} - 3 x^{2} - 10 x - 24 = 0

n^{8} + 12 = 64

y, 2 x^{3} = y - 11

What are the solutions to the equation (1-p)^{15}=0 ?
The solutions to the equation (1-p)^{15}=0 are p=1
Find the zeros of (1-p)^{15}=0
The zeros of (1-p)^{15}=0 are p=1