What are the solutions to the equation roots-x^3+5x^2-8x+4 ?

The solutions to the equation roots-x^3+5x^2-8x+4 are x=1,x=2

Find the zeros of roots-x^3+5x^2-8x+4

The zeros of roots-x^3+5x^2-8x+4 are x=1,x=2

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roots

- x^{3} + 5 x^{2} - 8 x + 4

x = 1, x = 2

Solution steps

- x^{3} + 5 x^{2} - 8 x + 4

The roots are the intercepts with the x-axis

(y = 0)

- x^{3} + 5 x^{2} - 8 x + 4 = 0

Factor

- x^{3} + 5 x^{2} - 8 x + 4 : - (x - 1) (x - 2)^{2}

- (x - 1) (x - 2)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x - 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

x - 2 = 0 : x = 2

The solutions are

x = 1, x = 2

x^{3} + 3 x^{2} - 4 x - 12 = 0

x^{3} - \frac{5}{6} x^{2} + \frac{35}{6} x + 1 = 0

6 x^{5} - 4 x^{3} = - 1

z^{12} = 1

4 m^{4} + 5 m^{2} - 9 = 0

What are the solutions to the equation roots-x^3+5x^2-8x+4 ?
The solutions to the equation roots-x^3+5x^2-8x+4 are x=1,x=2
Find the zeros of roots-x^3+5x^2-8x+4
The zeros of roots-x^3+5x^2-8x+4 are x=1,x=2