What are the solutions to the equation x(2x^2-1)=0 ?

The solutions to the equation x(2x^2-1)=0 are x=0,x=-1/(sqrt(2)),x= 1/(sqrt(2))

Find the zeros of x(2x^2-1)=0

The zeros of x(2x^2-1)=0 are x=0,x=-1/(sqrt(2)),x= 1/(sqrt(2))

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x (2 x^{2} - 1) = 0

x = 0, x = - \frac{1}{2}, x = \frac{1}{2}

Decimal Notation

x = 0, x = - 0.70710 \dots, x = 0.70710 \dots

Solution steps

x (2 x^{2} - 1) = 0

Factor

x (2 x^{2} - 1) : x (2 x + 1) (2 x - 1)

x (2 x + 1) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x + 1 = 0 or 2 x - 1 = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions are

x = 0, x = - \frac{1}{2}, x = \frac{1}{2}

2 x^{3} - 11 x^{2} + 12 x + 9 = 0

4 x^{4} - 4 x = 0

4 x - 7 x^{5} + 16 x^{2} = 0

x, 4 x^{3} - 2 x = 0

y, 8 y - 8 x^{3} = 0

What are the solutions to the equation x(2x^2-1)=0 ?
The solutions to the equation x(2x^2-1)=0 are x=0,x=-1/(sqrt(2)),x= 1/(sqrt(2))
Find the zeros of x(2x^2-1)=0
The zeros of x(2x^2-1)=0 are x=0,x=-1/(sqrt(2)),x= 1/(sqrt(2))