What are the solutions to the equation 2x^4-9x^3+6x^2+11x-6=0 ?

The solutions to the equation 2x^4-9x^3+6x^2+11x-6=0 are x=-1,x=2,x= 1/2 ,x=3

Find the zeros of 2x^4-9x^3+6x^2+11x-6=0

The zeros of 2x^4-9x^3+6x^2+11x-6=0 are x=-1,x=2,x= 1/2 ,x=3

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2 x^{4} - 9 x^{3} + 6 x^{2} + 11 x - 6 = 0

x = - 1, x = 2, x = \frac{1}{2}, x = 3

Decimal Notation

x = - 1, x = 2, x = 0.5, x = 3

Solution steps

2 x^{4} - 9 x^{3} + 6 x^{2} + 11 x - 6 = 0

Factor

2 x^{4} - 9 x^{3} + 6 x^{2} + 11 x - 6 : (x + 1) (x - 2) (2 x - 1) (x - 3)

(x + 1) (x - 2) (2 x - 1) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 2 = 0 or 2 x - 1 = 0 or x - 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 2 = 0 : x = 2

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

x - 3 = 0 : x = 3

The solutions are

x = - 1, x = 2, x = \frac{1}{2}, x = 3

x^{4} - 2 x^{3} + 5 x^{2} - 8 x + 4 = 0

\frac{x ^{3}}{7} - 21 x = 0

2 x^{4} - 3 x^{3} - 7 x^{2} - 8 x + 6 = 0

- 3 x^{3} + 4 x^{2} - 12 x + 16 = 0

a^{3} + 3 a^{2} + 2 a = 0

What are the solutions to the equation 2x^4-9x^3+6x^2+11x-6=0 ?
The solutions to the equation 2x^4-9x^3+6x^2+11x-6=0 are x=-1,x=2,x= 1/2 ,x=3
Find the zeros of 2x^4-9x^3+6x^2+11x-6=0
The zeros of 2x^4-9x^3+6x^2+11x-6=0 are x=-1,x=2,x= 1/2 ,x=3