What are the solutions to the equation x^3-6x^2+7x=0 ?

The solutions to the equation x^3-6x^2+7x=0 are x=0,x=3+sqrt(2),x=3-sqrt(2)

Find the zeros of x^3-6x^2+7x=0

The zeros of x^3-6x^2+7x=0 are x=0,x=3+sqrt(2),x=3-sqrt(2)

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x^{3} - 6 x^{2} + 7 x = 0

x = 0, x = 3 + 2, x = 3 - 2

Decimal Notation

x = 0, x = 4.41421 \dots, x = 1.58578 \dots

Solution steps

x^{3} - 6 x^{2} + 7 x = 0

Factor

x^{3} - 6 x^{2} + 7 x : x (x^{2} - 6 x + 7)

x (x^{2} - 6 x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} - 6 x + 7 = 0

Solve

x^{2} - 6 x + 7 = 0 : x = 3 + 2, x = 3 - 2

The solutions are

x = 0, x = 3 + 2, x = 3 - 2

3 x^{3} - 25 x^{2} + 58 x - 40

6 x^{3} = 0

x^{3} + 2 x^{2} - 11 x - 12

- 39 = 1 - 5 x^{9}

x^{5} - 16 x + 9 = 0

What are the solutions to the equation x^3-6x^2+7x=0 ?
The solutions to the equation x^3-6x^2+7x=0 are x=0,x=3+sqrt(2),x=3-sqrt(2)
Find the zeros of x^3-6x^2+7x=0
The zeros of x^3-6x^2+7x=0 are x=0,x=3+sqrt(2),x=3-sqrt(2)