What are the solutions to the equation r^4+2r^3+2r^2=0 ?

The solutions to the equation r^4+2r^3+2r^2=0 are r=0,r=-1+i,r=-1-i

Find the zeros of r^4+2r^3+2r^2=0

The zeros of r^4+2r^3+2r^2=0 are r=0,r=-1+i,r=-1-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

r^{4} + 2 r^{3} + 2 r^{2} = 0

r = 0, r = - 1 + i, r = - 1 - i

Solution steps

r^{4} + 2 r^{3} + 2 r^{2} = 0

Factor

r^{4} + 2 r^{3} + 2 r^{2} : r^{2} (r^{2} + 2 r + 2)

r^{2} (r^{2} + 2 r + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

r = 0 or r^{2} + 2 r + 2 = 0

Solve

r^{2} + 2 r + 2 = 0 : r = - 1 + i, r = - 1 - i

The solutions are

r = 0, r = - 1 + i, r = - 1 - i

2 x^{3} - 17 x^{2} = 9 x

x^{3} - 10 x + 4 = 0

x^{3} + x^{2} + x = - \frac{1}{3}

u^{3} - 64 = 0

r^{3} + r^{2} - 23 r - 35 = 0

What are the solutions to the equation r^4+2r^3+2r^2=0 ?
The solutions to the equation r^4+2r^3+2r^2=0 are r=0,r=-1+i,r=-1-i
Find the zeros of r^4+2r^3+2r^2=0
The zeros of r^4+2r^3+2r^2=0 are r=0,r=-1+i,r=-1-i