What are the solutions to the equation roots x^3-2x^2-6x-8 ?

The solutions to the equation roots x^3-2x^2-6x-8 are x=4,x=-1+i,x=-1-i

Find the zeros of roots x^3-2x^2-6x-8

The zeros of roots x^3-2x^2-6x-8 are x=4,x=-1+i,x=-1-i

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roots

x^{3} - 2 x^{2} - 6 x - 8

x = 4, x = - 1 + i, x = - 1 - i

Solution steps

x^{3} - 2 x^{2} - 6 x - 8

The roots are the intercepts with the x-axis

(y = 0)

x^{3} - 2 x^{2} - 6 x - 8 = 0

Factor

x^{3} - 2 x^{2} - 6 x - 8 : (x - 4) (x^{2} + 2 x + 2)

(x - 4) (x^{2} + 2 x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 = 0 or x^{2} + 2 x + 2 = 0

Solve

x - 4 = 0 : x = 4

Solve

x^{2} + 2 x + 2 = 0 : x = - 1 + i, x = - 1 - i

The solutions are

x = 4, x = - 1 + i, x = - 1 - i

y^{3} - 9 y^{2} + 27 y = 47

9 x^{8} - 9 = 0

x^{3} - x^{2} = 1

x^{3} - 2 x^{2} + x + 18 = 0

x^{3} + 3 x^{2} - 25 x + 21

What are the solutions to the equation roots x^3-2x^2-6x-8 ?
The solutions to the equation roots x^3-2x^2-6x-8 are x=4,x=-1+i,x=-1-i
Find the zeros of roots x^3-2x^2-6x-8
The zeros of roots x^3-2x^2-6x-8 are x=4,x=-1+i,x=-1-i