Solution
Solution
+1
Solution steps
Move to the right side
Divide both sides by
For the solutions are
Solve
Solve
The solutions to the quadratic equation are:
Popular Examples
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Frequently Asked Questions (FAQ)
What are the solutions to the equation 4(x+3)^2-5=27 ?
The solutions to the equation 4(x+3)^2-5=27 are x=2sqrt(2)-3,x=-2sqrt(2)-3Find the zeros of 4(x+3)^2-5=27
The zeros of 4(x+3)^2-5=27 are x=2sqrt(2)-3,x=-2sqrt(2)-3