What are the solutions to the equation (1+12x^2)^3=0 ?

The solutions to the equation (1+12x^2)^3=0 are x= 1/(2sqrt(3))i,x=-1/(2sqrt(3))i

Find the zeros of (1+12x^2)^3=0

The zeros of (1+12x^2)^3=0 are x= 1/(2sqrt(3))i,x=-1/(2sqrt(3))i

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(1 + 12 x^{2})^{3} = 0

x = \frac{1}{2 3} i, x = - \frac{1}{2 3} i

Solution steps

(1 + 12 x^{2})^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

1 + 12 x^{2} = 0 : x = \frac{1}{2 3} i, x = - \frac{1}{2 3} i

The solutions are

x = \frac{1}{2 3} i, x = - \frac{1}{2 3} i

2 x^{3} - 14 x^{2} + 2 x - 14 = 0

24 x^{3} + 46 x^{2} + 9 x - 9 = 0

r^{4} + 6 r^{3} + 17 r^{2} + 22 r + 14 = 0

x^{3} - x^{2} - 37 x - 35

x^{3} + 5 = 6 x^{2} + 3 x

What are the solutions to the equation (1+12x^2)^3=0 ?
The solutions to the equation (1+12x^2)^3=0 are x= 1/(2sqrt(3))i,x=-1/(2sqrt(3))i
Find the zeros of (1+12x^2)^3=0
The zeros of (1+12x^2)^3=0 are x= 1/(2sqrt(3))i,x=-1/(2sqrt(3))i