What are the solutions to the equation 9x^3+12x^2+4x=0 ?

The solutions to the equation 9x^3+12x^2+4x=0 are x=0,x=-2/3

Find the zeros of 9x^3+12x^2+4x=0

The zeros of 9x^3+12x^2+4x=0 are x=0,x=-2/3

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9 x^{3} + 12 x^{2} + 4 x = 0

x = 0, x = - \frac{2}{3}

Decimal Notation

x = 0, x = - 0.66666 \dots

Solution steps

9 x^{3} + 12 x^{2} + 4 x = 0

Factor

9 x^{3} + 12 x^{2} + 4 x : x (3 x + 2)^{2}

x (3 x + 2)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 3 x + 2 = 0

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

The solutions are

x = 0, x = - \frac{2}{3}

x^{4} - x^{3} - x^{2} - x - 1 = 0

x^{3} + 2 x^{2} + 4 x + 8

c^{3} + 2 c = 3

x^{3} + x^{2} - 2 = 0

4 x^{4} - 36 x^{2} = 0

What are the solutions to the equation 9x^3+12x^2+4x=0 ?
The solutions to the equation 9x^3+12x^2+4x=0 are x=0,x=-2/3
Find the zeros of 9x^3+12x^2+4x=0
The zeros of 9x^3+12x^2+4x=0 are x=0,x=-2/3