What are the solutions to the equation roots x^3+27 ?

The solutions to the equation roots x^3+27 are x=-3,x= 3/2-(3sqrt(3))/2 i,x= 3/2+(3sqrt(3))/2 i

Find the zeros of roots x^3+27

The zeros of roots x^3+27 are x=-3,x= 3/2-(3sqrt(3))/2 i,x= 3/2+(3sqrt(3))/2 i

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roots

x^{3} + 27

x = - 3, x = \frac{3}{2} - \frac{3 3}{2} i, x = \frac{3}{2} + \frac{3 3}{2} i

Solution steps

x^{3} + 27

The roots are the intercepts with the x-axis

(y = 0)

x^{3} + 27 = 0

Move

27

to the right side

x^{3} = - 27

For

x^{3} = f (a)

the solutions are

Simplify

x = - 3, x = \frac{3}{2} - \frac{3 3}{2} i, x = \frac{3}{2} + \frac{3 3}{2} i

4 x^{3} - 24 x^{2} + 48 x = 0

9 x^{3} + 45 x^{2} + 59 x + 15

64 m = m^{3} - m^{2} + m - 62

3 x^{3} - x^{2} - 4 x = 0

2 x^{2} + 5 = (x^{2} + 1)^{2}

What are the solutions to the equation roots x^3+27 ?
The solutions to the equation roots x^3+27 are x=-3,x= 3/2-(3sqrt(3))/2 i,x= 3/2+(3sqrt(3))/2 i
Find the zeros of roots x^3+27
The zeros of roots x^3+27 are x=-3,x= 3/2-(3sqrt(3))/2 i,x= 3/2+(3sqrt(3))/2 i