What are the solutions to the equation factor 3x^4-8x^2=-4 ?

The solutions to the equation factor 3x^4-8x^2=-4 are x=-sqrt(2/3),x=sqrt(2/3),x=-sqrt(2),x=sqrt(2)

Find the zeros of factor 3x^4-8x^2=-4

The zeros of factor 3x^4-8x^2=-4 are x=-sqrt(2/3),x=sqrt(2/3),x=-sqrt(2),x=sqrt(2)

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factor

3 x^{4} - 8 x^{2} = - 4

x = - \frac{2}{3}, x = \frac{2}{3}, x = - 2, x = 2

Decimal Notation

x = - 0.81649 \dots, x = 0.81649 \dots, x = - 1.41421 \dots, x = 1.41421 \dots

Solution steps

3 x^{4} - 8 x^{2} = - 4

Move

4

to the left side

3 x^{4} - 8 x^{2} + 4 = 0

Factor

3 x^{4} - 8 x^{2} + 4 : (3 x + 2) (3 x - 2) (x + 2) (x - 2)

(3 x + 2) (3 x - 2) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 2 = 0 or 3 x - 2 = 0 or x + 2 = 0 or x - 2 = 0

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

Solve

3 x - 2 = 0 : x = \frac{2}{3}

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = - \frac{2}{3}, x = \frac{2}{3}, x = - 2, x = 2

x^{2} 5 x + 1 = 3 x^{2} + 6

7 x^{4} - 112 = 0

m^{3} + 4 m^{2} + 5 m + 2 = 0

x^{4} - 22 x^{2} + x + 114 = 0

2 x^{2} - x^{4} = 0

What are the solutions to the equation factor 3x^4-8x^2=-4 ?
The solutions to the equation factor 3x^4-8x^2=-4 are x=-sqrt(2/3),x=sqrt(2/3),x=-sqrt(2),x=sqrt(2)
Find the zeros of factor 3x^4-8x^2=-4
The zeros of factor 3x^4-8x^2=-4 are x=-sqrt(2/3),x=sqrt(2/3),x=-sqrt(2),x=sqrt(2)