What are the solutions to the equation roots x^3-3x^2-10x+24 ?

The solutions to the equation roots x^3-3x^2-10x+24 are x=2,x=-3,x=4

Find the zeros of roots x^3-3x^2-10x+24

The zeros of roots x^3-3x^2-10x+24 are x=2,x=-3,x=4

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roots

x^{3} - 3 x^{2} - 10 x + 24

x = 2, x = - 3, x = 4

Solution steps

x^{3} - 3 x^{2} - 10 x + 24

The roots are the intercepts with the x-axis

(y = 0)

x^{3} - 3 x^{2} - 10 x + 24 = 0

Factor

x^{3} - 3 x^{2} - 10 x + 24 : (x - 2) (x + 3) (x - 4)

(x - 2) (x + 3) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 3 = 0 or x - 4 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 3 = 0 : x = - 3

Solve

x - 4 = 0 : x = 4

The solutions are

x = 2, x = - 3, x = 4

\frac{Q ^{3}}{3} - 10 Q^{2} + 80 Q + 648 = 4 Q

x^{3} + x^{2} - 17 x + 15

x^{3} - x^{2} - 25 x + 25 = 0

- 19 x^{3} - 12 x^{2} + 16 x = 0

3 y^{3} - 20 y^{2} - 7 y = 0

What are the solutions to the equation roots x^3-3x^2-10x+24 ?
The solutions to the equation roots x^3-3x^2-10x+24 are x=2,x=-3,x=4
Find the zeros of roots x^3-3x^2-10x+24
The zeros of roots x^3-3x^2-10x+24 are x=2,x=-3,x=4