What are the solutions to the equation roots x^4-2x^3-8x^2+18x-9=0 ?

The solutions to the equation roots x^4-2x^3-8x^2+18x-9=0 are x=1,x=-3,x=3

Find the zeros of roots x^4-2x^3-8x^2+18x-9=0

The zeros of roots x^4-2x^3-8x^2+18x-9=0 are x=1,x=-3,x=3

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roots

x^{4} - 2 x^{3} - 8 x^{2} + 18 x - 9 = 0

x = 1, x = - 3, x = 3

Solution steps

x^{4} - 2 x^{3} - 8 x^{2} + 18 x - 9 = 0

Factor

x^{4} - 2 x^{3} - 8 x^{2} + 18 x - 9 : (x - 1)^{2} (x + 3) (x - 3)

(x - 1)^{2} (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 3 = 0 or x - 3 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = 1, x = - 3, x = 3

7 x^{3} - 35 x^{2} - 252 x = 0

y^{3} = 64 y

2 = y^{3} + 2 y - 1

x^{4} + 4 x - 2 = 0

x^{3} + 2 x^{2} - 200 x - 20 = 0

What are the solutions to the equation roots x^4-2x^3-8x^2+18x-9=0 ?
The solutions to the equation roots x^4-2x^3-8x^2+18x-9=0 are x=1,x=-3,x=3
Find the zeros of roots x^4-2x^3-8x^2+18x-9=0
The zeros of roots x^4-2x^3-8x^2+18x-9=0 are x=1,x=-3,x=3