What are the solutions to the equation -4x^3+3x^2+2x=0 ?

The solutions to the equation -4x^3+3x^2+2x=0 are x=0,x=(3+sqrt(41))/8 ,x=(3-sqrt(41))/8

Find the zeros of -4x^3+3x^2+2x=0

The zeros of -4x^3+3x^2+2x=0 are x=0,x=(3+sqrt(41))/8 ,x=(3-sqrt(41))/8

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- 4 x^{3} + 3 x^{2} + 2 x = 0

x = 0, x = \frac{3 + 41}{8}, x = \frac{3 - 41}{8}

Decimal Notation

x = 0, x = 1.17539 \dots, x = - 0.42539 \dots

Solution steps

- 4 x^{3} + 3 x^{2} + 2 x = 0

Factor

- 4 x^{3} + 3 x^{2} + 2 x : - x (4 x^{2} - 3 x - 2)

- x (4 x^{2} - 3 x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 4 x^{2} - 3 x - 2 = 0

Solve

4 x^{2} - 3 x - 2 = 0 : x = \frac{3 + 41}{8}, x = \frac{3 - 41}{8}

The solutions are

x = 0, x = \frac{3 + 41}{8}, x = \frac{3 - 41}{8}

0 = 4 x^{3} - 4

v^{3} - 4 v = 0

4 x^{3} - 256 x = 0

x, x^{3} + y^{3} + z^{3} = 42

- 6 x^{4} + 38 x^{3} - 45 x^{2} + 26 x - 5

What are the solutions to the equation -4x^3+3x^2+2x=0 ?
The solutions to the equation -4x^3+3x^2+2x=0 are x=0,x=(3+sqrt(41))/8 ,x=(3-sqrt(41))/8
Find the zeros of -4x^3+3x^2+2x=0
The zeros of -4x^3+3x^2+2x=0 are x=0,x=(3+sqrt(41))/8 ,x=(3-sqrt(41))/8