What are the solutions to the equation (x+3)^2+(x+3)-2=0 ?

The solutions to the equation (x+3)^2+(x+3)-2=0 are x=-2,x=-5

Find the zeros of (x+3)^2+(x+3)-2=0

The zeros of (x+3)^2+(x+3)-2=0 are x=-2,x=-5

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(x + 3)^{2} + (x + 3) - 2 = 0

x = - 2, x = - 5

Solution steps

(x + 3)^{2} + (x + 3) - 2 = 0

Expand

(x + 3)^{2} + (x + 3) - 2 : x^{2} + 7 x + 10

x^{2} + 7 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 10 = 3

x_{1, 2} = \frac{- 7 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 3}{2 \cdot 1}, x_{2} = \frac{- 7 - 3}{2 \cdot 1}

x = \frac{- 7 + 3}{2 \cdot 1} : - 2

x = \frac{- 7 - 3}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = - 2, x = - 5

(2 0^{\frac{1}{3}})^{2}

∣ x + 3 ∣ \geq - 9

27 m^{2} - 36 m + 12

6000 r p m^{1} \cdot \frac{2 π}{r p m}

(z + 9)^{2} = - 64

What are the solutions to the equation (x+3)^2+(x+3)-2=0 ?
The solutions to the equation (x+3)^2+(x+3)-2=0 are x=-2,x=-5
Find the zeros of (x+3)^2+(x+3)-2=0
The zeros of (x+3)^2+(x+3)-2=0 are x=-2,x=-5