What are the solutions to the equation 6x^3-35x^2+26x-5=0 ?

The solutions to the equation 6x^3-35x^2+26x-5=0 are x=5,x= 1/3 ,x= 1/2

Find the zeros of 6x^3-35x^2+26x-5=0

The zeros of 6x^3-35x^2+26x-5=0 are x=5,x= 1/3 ,x= 1/2

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6 x^{3} - 35 x^{2} + 26 x - 5 = 0

x = 5, x = \frac{1}{3}, x = \frac{1}{2}

Decimal Notation

x = 5, x = 0.33333 \dots, x = 0.5

Solution steps

6 x^{3} - 35 x^{2} + 26 x - 5 = 0

Factor

6 x^{3} - 35 x^{2} + 26 x - 5 : (x - 5) (3 x - 1) (2 x - 1)

(x - 5) (3 x - 1) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 5 = 0 or 3 x - 1 = 0 or 2 x - 1 = 0

Solve

x - 5 = 0 : x = 5

Solve

3 x - 1 = 0 : x = \frac{1}{3}

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions are

x = 5, x = \frac{1}{3}, x = \frac{1}{2}

480 = \frac{4}{3} π r^{3}

r^{4} - r = 0

y^{4} + 2 y^{3} + y^{2} + 8 y - 12 = 0

2 x^{3} - 5 x^{2} - 4 x + 3

2 x^{3} x^{3} = 1 8^{2}

What are the solutions to the equation 6x^3-35x^2+26x-5=0 ?
The solutions to the equation 6x^3-35x^2+26x-5=0 are x=5,x= 1/3 ,x= 1/2
Find the zeros of 6x^3-35x^2+26x-5=0
The zeros of 6x^3-35x^2+26x-5=0 are x=5,x= 1/3 ,x= 1/2