What are the solutions to the equation 16x^3+28x^2=0 ?

The solutions to the equation 16x^3+28x^2=0 are x=0,x=-7/4

Find the zeros of 16x^3+28x^2=0

The zeros of 16x^3+28x^2=0 are x=0,x=-7/4

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16 x^{3} + 28 x^{2} = 0

x = 0, x = - \frac{7}{4}

Decimal Notation

x = 0, x = - 1.75

Solution steps

16 x^{3} + 28 x^{2} = 0

Factor

16 x^{3} + 28 x^{2} : 4 x^{2} (4 x + 7)

4 x^{2} (4 x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 4 x + 7 = 0

Solve

4 x + 7 = 0 : x = - \frac{7}{4}

The solutions are

x = 0, x = - \frac{7}{4}

m^{4} + m^{3} + m^{2} = 0

m, 17 n^{2} + 29 m^{3} = 5492346

14 x (x^{2} - 4)^{6} = 0

x^{3} - 7 x + 6

120 t - 0.4 t^{4} + 800 = 0

What are the solutions to the equation 16x^3+28x^2=0 ?
The solutions to the equation 16x^3+28x^2=0 are x=0,x=-7/4
Find the zeros of 16x^3+28x^2=0
The zeros of 16x^3+28x^2=0 are x=0,x=-7/4